The cell problem H(x, P + u′) = H̄(P) has one number in it, and it is the number everyone computes: the effective Hamiltonian of homogenization, the Mañé critical value, the eigenvalue of weak KAM. Gomes and Yang compute it with a Hessian Riemannian flow and a Newton method, alongside the Mather measure, and test against the one case with a formula: one dimension, a mechanical Hamiltonian, where H̄ is flat up to a threshold and beyond it the inverse of an integral. This page encloses that formula. The flat part is decided exactly; the rising part is bracketed by bisection on a rigorously enclosed integral, closed by the mean value theorem; the threshold is enclosed and the one point inside its enclosure is left undecided, because that is where the problem degenerates and the integrand's second derivative goes to infinity. Then the paper's tables are held against the band, and the eight-digit value it quotes for the separable two-dimensional example is found one digit too generous.
For H = p²/2 + V(x) on the circle, the corrector u solves (P + u′)²/2 + V = H̄, so P + u′ = ±√(2(H̄ − V)). If H̄ = max V the root can change sign where V peaks, u′ can be arranged with any mean between −P₀ and P₀, and H̄ stays at max V: the flat part. Beyond P₀ the sign is fixed and the mean of P + u′ is the integral Q(H̄) = ∫√(2(H̄ − V)), so H̄ is the number with Q(H̄) = |P|. The paper quotes this (§6.1, from Cacace–Camilli) for V = sin 2πx with P₀ = 4/π.
Everything on this page is that formula evaluated as intervals. Q is strictly increasing (its derivative is the period ∫1/√(2(c − V)) > 0), so bisection brackets c whenever Q can be bounded above and below; Q is bounded by the midpoint rule with its remainder w³/24·sup|f″|, the second derivative carried through every operation as an interval. The trouble is where the formula is interesting: as c ↓ max V the integrand √(2(c − V)) develops a cusp at the peak of V and f″ grows like (c − V)^{−3/2}. Cells where the base is not positive by a margin fall back to a plain Riemann bound and the enclosure of Q widens toward P₀. Bisection stops when it cannot tell which side of |P| the integral is on; the mean value theorem, with the period ∫1/√(2(c − V)) as the derivative of Q, then turns the last straddling enclosure into a bracket on c. P₀ itself has the cusp on the nose; its enclosure is 1.5e-6 wide, it contains 4/π, and the one sampled P inside it is left undecided.
| P | regime | H̄(P) | width | Mather measure |
|---|---|---|---|---|
| 0 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 0.25 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 0.5 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 0.75 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 1 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 1.1 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 1.2 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 1.25 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 1.27 | FLAT | 1 | 0 (exact) | Dirac at x = 0.25 |
| 4/π | UNDECIDED | inside the P₀ enclosure | — | — |
| 1.275 | ROTATING | [1.000969246, 1.000970746] | 1.5e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 1.28 | ROTATING | [1.004282614, 1.004284129] | 1.5e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 1.29 | ROTATING | [1.011834807, 1.011836389] | 1.6e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 1.3 | ROTATING | [1.020098639, 1.020100268] | 1.6e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 1.35 | ROTATING | [1.067535157, 1.067536911] | 1.8e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 1.4 | ROTATING | [1.121762747, 1.121764564] | 1.8e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 1.5 | ROTATING | [1.244636699, 1.244638582] | 1.9e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 1.75 | ROTATING | [1.615905179, 1.615907130] | 2.0e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 2 | ROTATING | [2.063794435, 2.063796410] | 2.0e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 2.25 | ROTATING | [2.581256123, 2.581258110] | 2.0e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 2.5 | ROTATING | [3.165326627, 3.165328620] | 2.0e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
| 3 | ROTATING | [4.527885155, 4.527887155] | 2.0e-6 | absolutely continuous, density 1/(T(c)√(2(c − V))) |
On the rotating part the projected Mather measure is the time the orbit spends: m(x) = 1/(T(c)√(2(c − V(x)))) with T(c) the period ∫1/√(2(c − V)). Both are enclosed at P = 1.5 and P = 2; the density integrates to 1 to 1e−5 on the enclosure midpoints. On the flat part it is the Dirac mass at the maximum of V, x = ¼ for the sine — Mather's theorem, and the paper's own statement at P = P₀ (δ at ¾ for their −sin). The support of the Mather measure is therefore decided at every sampled P except the undecided one.
Table 1. The two-dimensional Hamiltonian |p|²/2 + cos 2πx₁ + cos 2πx₂ is separable, so H̄(P₁, P₂) = H̄(P₁) + H̄(P₂) with the one-dimensional cosine formula — the paper says so and quotes H̄(1.5, 2.5) = 4.4099660 from Gomes–Oberman (2004), then reports its own flow and Newton values at k = 10 to 10⁴. Both one-dimensional values are bracketed here to below 1e−6 with 8192 cells: c(1.5) ∈ [1.244637626, 1.244637655], c(2.5) ∈ [3.165327608, 3.165327639], sum [4.409965234, 4.409965294]. The quoted 4.4099660 lies above the enclosure by 7.1e-7: its seventh significant digit is not the value's. The paper's own numbers all lie below the enclosure, which is what they must do — the entropy-penalized H̄^k is a soft maximum and never exceeds H̄ — and its k = 10⁴ value 4.40996 agrees with the enclosure to every digit it prints.
| k | HRF (printed) | against the enclosure | Newton (printed) | against the enclosure |
|---|---|---|---|---|
| 10 | 4.40251 | BELOW | 4.40935 | BELOW |
| 100 | 4.40916 | BELOW | 4.40994 | BELOW |
| 1000 | 4.40989 | BELOW | 4.40996 | BELOW |
| 10000 | 4.40996 | BELOW | 4.40996 | BELOW |
Table 2. At P = 0.5 on −sin 2πx the paper says H̄ = 1 and reports H̄◇, the flow's large-time value at k = 100, for four meshes: 0.964609 to 0.96476. The exact value is decided here — 0.5 is below the lower end of the P₀ enclosure, so the point is FLAT and H̄ = 1 exactly — and the printed values sit 0.0354 to 0.0352 below it. The gap does not close from N = 60 to N = 120; it is the entropy penalization at k = 100, not the mesh, and the paper's Figure 1 shows the same gap shrinking with k.
| N | H̄◇ (printed, k = 100) | exact H̄(0.5) | gap |
|---|---|---|---|
| 15 | 0.964609 | 1 (FLAT, decided) | 0.035391 |
| 30 | 0.964754 | 1 (FLAT, decided) | 0.035246 |
| 60 | 0.964760 | 1 (FLAT, decided) | 0.035240 |
| 120 | 0.964760 | 1 (FLAT, decided) | 0.035240 |
node instruments/hbar/battery.js # 18 checks, 5 red controls: P₀ vs 4/π, brackets vs the trapezoid rule, the Mather mass, the tables node instruments/hbar/run.js --check # the record, re-derived and compared byte for byte
The instrument is instruments/hbar/exact.js with derive.js; the interval jet is instruments/interval/taylor2.js; the record is certs/hbar-band.json.